Question

what is the midpoint, of line BC if...
B is (11, 20) and
C is (0, 20).

Please help!

Answer 1

Hello :)
To get the midpoint of the line SEGMENT BC (Lines don't have midpoints, they have infinite length!)

Where
\[\large B=(x_1,y_1) \ \ \ C=(x_2,y_2)\]
You just get the average of their x and y coordinates...
Midpoint is given by
\[\large M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\]

Answer 2

Then it's (5, 20). Correct?

Answer 3

How do you get 5?

Answer 4

0+ 10=10
10/2= 5

Answer 5

why 10? It's 11.
That's what you posted, at least
(11 , 20)
( 0 , 20)

Answer 6

http://mathway.com/answer.aspx?p=calg?p=(11,20)SMB15(0,20)?p=165?p=?p=?p=?p=?p=0?p=?p=0?p=?p=?p=FindSMB15theSMB15Midpoint