Let f(x) = ax³ - bx + 2 where a and b are constants. If f(4) = -5, then f(-4) = ? A) 9 B) 5 C) 1 D) -1 E) -4
Do you have an idea about what the answer is?
No idea.
It just seems like there is not enough given information...
I am guessing that, because if f(4)= -5 that the f(-4)= (-5 x -1) Because 4 x -1 = -4
if that makes sense
But f(x) is neither even nor odd function...
It doesn't make sense to me.
I am just ignoring the first part..
@Mertsj Do you know if I am right?
plug in x = 4 and y = -5 to get one equation in terms of a and b then plug in x = -4 to get another equation in terms of 'a' and b then add the two equations
afterwards, solve for y
Huh? @jim_thompson5910
y = a*x^3-b*x+2 -5 = a*(4)^3-b*(4)+2 -5 = 64a - 4b + 2 -5 - 2 = 64a - 4b 64a - 4b = -7
y = a*x^3-b*x+2 y = a*(-4)^3-b*(-4)+2 y = -64a+4b+2 -64a + 4b + 2 = y
add the two equations 64a - 4b = -7 -64a + 4b + 2 = y ------------------ 0a + 0b + 2 = -7 + y which gives us 2 = -7 + y
Thanks!
Oh.
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