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OpenStudy (anonymous):
try substitution
t=x^2
dt=2xdx
1/2dt=xdx
OpenStudy (anonymous):
can i do partial fraction method?
OpenStudy (agent0smith):
\[\int\limits \frac{ 2 }{ x (x^2+1)^2} dx\]
Hmm. Use partial fractions?
OpenStudy (anonymous):
yes you can use partial fraction . i guess fractions will be easy with linear terms
so use
t=x^2
dt=2xdx
\[\Large \int\limits \frac{dt}{t(t+1)^2}\]
now use partial fractions .
OpenStudy (anonymous):
no
we can write the original integral as
\[\Large \int\limits \frac{2xdx}{x^2(x^2+1)}\]
so
let
t=x^2
dt=2xdx
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you can use partial fraction, this is because if the power of the denominator is greater than the power of the numerator that would be an alternative method...
OpenStudy (anonymous):
but for me personal i prefer the first method present by sami....
OpenStudy (anonymous):
okay thank you!
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