Question

Factor: (-x^2 -2x +8) / (2-x)

Answer 1

I'm assuming that you want to factor the top line so that you could divide easily. For that, first split the middle term.\[-x^2 + 2x - 4x + 8\]Can you continue?

Answer 2

Why should I split terms

Answer 3

@ParthKohli

Answer 4

That's what you do in order to factor any quadratic!

Answer 5

just about any quadratic?

Answer 6

http://www.mathsisfun.com/algebra/factoring.html

Answer 7

Take for example \(2x^2 + 8x + 8\). Split it into \(2x^2 + 4x + 4x + 8 \iff 2x(x + 2) + 4(x + 2) \iff (2x + 4)(x + 2)\)

Answer 8

lets see I will manage to solve this finally

Answer 9

All quadratics with rational roots!

Answer 10

\[-x ^{2}-2x+8\]
After splitting the middle term -2x into 2x - 4x we get
\[-x ^{2}+2x-4x+8\]
Factorising the first two terms and the last two terms we get
\[x(-x+2)+4(-x+2)\]
Then taking out the common factor gives
\[(2-x)(x+4)\]