Factor: (-x^2 -2x +8) / (2-x)

Question

parthkohli · Answer

I'm assuming that you want to factor the top line so that you could divide easily. For that, first split the middle term.$$-x^2 + 2x - 4x + 8$$Can you continue?

christos · Answer

Why should I split terms

christos · Answer

@ParthKohli

parthkohli · Answer

That's what you do in order to factor any quadratic!

christos · Answer

just about any quadratic?

anonymous · Answer

http://www.mathsisfun.com/algebra/factoring.html

parthkohli · Answer

Take for example $2x^2 + 8x + 8$. Split it into $2x^2 + 4x  + 4x + 8 \iff 2x(x + 2) + 4(x + 2) \iff (2x + 4)(x + 2)$

christos · Answer

lets see I will manage to solve this finally

parthkohli · Answer

All quadratics with rational roots!

kropot72 · Answer

$$-x ^{2}-2x+8$$
After splitting the middle term -2x into 2x - 4x we get
$$-x ^{2}+2x-4x+8$$
Factorising the first two terms and the last two terms we get
$$x(-x+2)+4(-x+2)$$
Then taking out the common factor gives
$$(2-x)(x+4)$$