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Simplify the expression \[\sqrt{ #4 } \] divided by (5 + 2i) - (3 - 4i)
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\[\frac{\sqrt{4}}{5+2i-(3-4i)}\]
multiply by conjugate of the denominator, which is 2+2i
Is that the problem?
yes, mertsj
i put 5 + 2i in parentheses, but it doesn't really matter either way
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okay myoko
so multiply bouth nominator and denominator by 2+2i and see what you get
numerator would be 3
\[\frac{\sqrt4(2+2i)}{(2-2i)(2+2i)}=\frac{\sqrt4(2+2i)}{8}=+-\frac{2+2i}{4}\]
+-(1/2+1/2i)
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the conjugate of the denominator is 2-6i
right. Ty @sirm3d
just change 2+2i for 2-6i and perfomr the operations
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