Question

sin(sin-1π) = ?
i do not remember our lesson on this from friday.

Answer 1

first off, you don't need to bother with the one in front of pi, and \[\sin(a+b)=\sin(a)\cos(b)+\sin(b)\cos(a)\] keep that one handy. so use this expansion

Answer 2

sorry that isn't a one, thats inverse sin

Answer 3

oh
well when you have \[sinx = a \] how do you get the value of x? you take the inverse, so that means \[\arcsin(sinx) =sina\] \[acrsin(sinx)=x = sina\]

Answer 4

so it = π?

Answer 5

it is not in -π/2 to π/2 though

Answer 6

yes it is :) from -pi/2 to pi/2 is a full rotation, which is going to include pi