Question

One saline solution contains .75 g NaCl in exactly 100 mL of solution. What is the molarity of the solution?

Answer 1

.75 g in 100 mL = 7.5 g in 1000 mL=7.5 g in 1 L. How many moles is 7.5 g NaCl?

Answer 2

\[Molarity=\frac{ moles _{NaCl} }{L _{solution} }=\frac{ (\frac{ mass _{NaCl} }{ molarmass _{NaCl} }) }{L _{solution} }\]