Question

x^2-2/3=0
How do I solve for x?

Answer 1

Difference of squares:\[(x+y)(x-y)=x^2-y^2\]So, factoring x^2 - 2/3 = 0 through difference of squares gives us:\[(x+\sqrt {2/3})(x-\sqrt {2/3}) = x^2-2/3=0\]\[x=\pm \sqrt{2/3}\]

Answer 2

@revernt

Answer 3

multiply by 3 and group like term ie 3x^2=2 and result is +or- square root of 2/3

Answer 4

thanks!