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How to solve 2e^ln x + 3 = 6?
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first off \[e^{\ln(x)}=x\]
because the log and the exponential functions are inverses it is not clear exactly if you meant \[2e^{\ln(x)=3}=6\] or \[2e^{\ln(x)}+3=6\]
the answer will be different depending on which it is is it the first one of the second one?
It would be the second one. @satellite73
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