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need help (x^3+y^2)(x^3-y^2) can someone help me figure this out and explain?
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you have to do four multiplications
I need to multiply
\[x^3\times x^3\] is the first one
x^6? do I add the exponents?
then \(x^3\times (-y^2)\)
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yes
then \(x^3\times y^2\)
and finally \(y^2\times (-y)^2\)
x^6-y^4?
you will notice that middle terms add up to zero, so you are only left with \[x^6-y^4\]
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yes
it is always true that \((a+b)(a-b)=a^2-b^2\)
see, all I need is confidence and your great guidings! :) I might make it after all. LOL
you can also use a table to help you multiply |dw:1362367881354:dw|
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