find the slope intercept form for the line satisfying the following conditions.
x intercept 2, y intercept 2/3

Question

find the slope intercept form for the line satisfying the following conditions.  
x intercept 2, y intercept 2/3

anonymous · Answer

this gives you two points (2,0) and (0,2/3)

tkhunny · Answer

The Interecpt Form
$\dfrac{x}{2} + \dfrac{y}{2/3} = 1$

After a little algebra...

anonymous · Answer

the slope is 1?

tkhunny · Answer

Who said that?  You task is to find the Slope-Intercept Form.

@tomo showed you taht you have two points.
I showed you the Intercept Form.

Now, go!  Find the Slope Intercept form.

anonymous · Answer

@tkhunny and @tomo yeah, I don't understand it either. How is she supposed to do that with a fraction under another fraction (the y/2/3)??? I just would like to know how's that's done.

tkhunny · Answer

Please do not tell me that you do not know how to multiply of divide fractions.

$\dfrac{x}{2} + \dfrac{y}{2/3} = 1$

Reciprocal and Multiply
$\dfrac{x}{2} + \dfrac{3y}{2} = 1$

Now, can you solve for y?

tkhunny · Answer

Where did the equal sign go?
Why doesn't it say "y = "?

$\dfrac{x}{2} + \dfrac{3y}{2} = 1$

Multiply by 2

$x + 3y = 2$

Now, can you solve for y?

anonymous · Answer

@tkhunny 

Divide both sides by 2 and get 1???

$$ \frac{ 3y }{ 2 } = \frac{ 2 }{ 2 }$$
=1

Is that correct?

anonymous · Answer

so, x = 1???? @tkhunny

tkhunny · Answer

Where did the x go?
Where did the y go?

x+3y=2 

Subtract x from both sides.

3y = -x + 2

Now can you solve for y?

Why are you struggling with this?  You should have solved about 400 similar equations for a given variable by now.  Is this your first?  Are you in the right class?  Is your online format providing no informatino whatsoever?  Seriously, something is not right, here.  I blame your teacher or your curriculum or your format - not you.  You should be given the tools you need.  It appears you don't have them.

anonymous · Answer

I just... don't understand. I'm sorry if your ticked @tkhunny .  :) I'll stop. Hope the girl that asked this question figure this out! :D @Jasmineplayhouse  Have fun!

tkhunny · Answer

If I have any anger, it is with those who haven't prepared you with the right tools.  All I'm saying is that there is a disconnect, here.  Let's figure out where it is.  You may be in the wrong class.  I'm not sure.

Have you solved equations before?

3x = 6

Can you solve that for x?  What value for x makes hte equality true?

2y - 5 = 3

Can yousolve that for y?  What value for y makes the equality true?

Let's see where you are?