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Choose the correct simplification of the expression (3xy^4)^2(y^2)^3. 6x^2y^14 9x^2y^14 9x^3y^11 6x^3y^11
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medal and fan to best answer/explaination
since \(3^2=9\) you can forget 1 and 4
im thinkin its 2
\[ (3xy^4)^2(y^2)^3\] square everything first, i.e. multiply all the exponents by 2
9x^2y^11
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you distribute the exponents outside of the parentheses to all the terms inside the parentheses
then \[3^2x^4y^8\times y^6\] now add up the exponents
you get \[9x^2y^{14}\]
oops i made a mistake above, there is no \(x^4\) term it is \(x^2\)
you are right, it is 2
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thanks !!
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