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Mathematics 14 Online
OpenStudy (anonymous):

Choose the correct simplification of the expression (3xy^4)^2(y^2)^3. 6x^2y^14 9x^2y^14 9x^3y^11 6x^3y^11

OpenStudy (anonymous):

medal and fan to best answer/explaination

OpenStudy (anonymous):

since \(3^2=9\) you can forget 1 and 4

OpenStudy (anonymous):

im thinkin its 2

OpenStudy (anonymous):

\[ (3xy^4)^2(y^2)^3\] square everything first, i.e. multiply all the exponents by 2

OpenStudy (anonymous):

9x^2y^11

OpenStudy (anonymous):

you distribute the exponents outside of the parentheses to all the terms inside the parentheses

OpenStudy (anonymous):

then \[3^2x^4y^8\times y^6\] now add up the exponents

OpenStudy (anonymous):

you get \[9x^2y^{14}\]

OpenStudy (anonymous):

oops i made a mistake above, there is no \(x^4\) term it is \(x^2\)

OpenStudy (anonymous):

you are right, it is 2

OpenStudy (anonymous):

thanks !!

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