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Find all solutions in the interval [0, 2π). tan x + sec x = 1
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@Mertsj
Change everything to sine and cosine
im not sure how to do that @Mertsj
What is the definition of tangent?
opposite/adjacent
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In terms of sin and cosine?
sin x /cos x
yes. And what is sec?
1/cos x
Yes. So now we have:
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sin x /cos x + 1/ cos x =1 ?
\[\frac{\sin x}{cosx}+\frac{1}{\cos x}=1\]
So multiply each term by cos x
sinxcosx + cosx = cosx
@Mertsj
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\[\frac{\sin x}{\cos x}\times cosx +\frac{1}\cos x \times \cos x=1\times \cos x\]
sin x + cos x = cos x ?
@Mertsj
sinx + 1 = cosx
now what do i do?
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x = x = 0 x = No solution
x = π/4 x = 0 x = 5π/4 No solution
@Mertsj
no solution
thank u
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No wait. I think that 0 might work.
Try it
i did. its 0. @Mertsj
Good.
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