Question

can anyone explain how the equation got 13/4?

Answer 1

The displacement (in meter) of an object moving in a straigt line is given by s=1+2t+1/4(t^2)
a) find the avarage veolocity over each time period

Answer 2

the answer says
\[f(x)=\frac{ s(1+h)-s(1) }{ (1+h)-1 }=\frac{ 1+2(1+h)+(1+h)^2/4-13/4 }{ h }\]

Answer 3

@Twis7ed

Answer 4

why they got -13/4 in the end?

Answer 5

That is the value of s(1)

Answer 6

what do you mean by that?

Answer 7

Do you understand the first step they took? The s(1+h)-s(1)/(1+h)-1?

Answer 8

Yes, I understand that part.

Answer 9

Ok, then the 13/4 is the value of the s(1) part of the equation

Answer 10

Since you get 13/4 when you plug in 1 for the x in your s(x) function

Answer 11

which equation?

Answer 12

s(1+h)−s(1)/(1+h)−1

Answer 13

oh I see.... but i am still confused about -13/4

Answer 14

In the equation s(1+h)−s(1)/(1+h)−1, the part that says s(1) is basically the value of the equation s(x) which they gave you, when x=1 so you can just plug in 1 for x and solve and you end up getting 13/4

Answer 15

ohh I see. so the equation told me is equation for any velocity problem?

Answer 16

the equation ( you told me)