Question

implicit differentiation
ln(7+e^xy)=y

Answer 1

This is what im learning right now!

Answer 2

do you know how to do it

Answer 3

take derivative of both sides. \[\dfrac{d}{dx}\ln(\space f(x) \space) = \dfrac{f'(x)}{f(x)} \]

Answer 4

So \(\dfrac{d}{dx}\ln (7+e^{xy}) = \dfrac{\dfrac{d}{dx}(7+e^{xy})}{7+e^{xy}} = y'\)

Answer 5

Can you handle it now?

Answer 6

what do I do from there

Answer 7

You'll have to keep applying the chain rule.

So, focus on \[\frac{ d }{ dx } (7+e^{xy})\]

\[e^{xy} \frac{ d }{ dx } (xy)\]

What's the next step? Hint: product rule.