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MIT 18.01 Single Variable Calculus (OCW)
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On the answer sheet for problem set one (http://ocw.mit.edu/courses/mathematics/18-01-single-variable-calculus-fall-2006/readings/s_solutns_exrcis.pdf), 5A-1c), it states that tan θ = 5 implies that sin θ = 5/(26)^1/2. How and why are we supposed to imply this?
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Not sure if this helps, but when I plug the numbers into the calculator, the answer follows straight away. So I guess the implication is directly by calculating the sine of the inverse tangent of 5.
The trigonometric functions refer to a ratio with right triangles, so you can draw a triangle and label it to match the equation you have. Then you can figure out the other trig identities. |dw:1363134213188:dw|
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