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Physics 14 Online
OpenStudy (anonymous):

Question....intuitive....(I don't have much intuition sadly)

OpenStudy (anonymous):

OpenStudy (experimentx):

hmm ... what has remained constant?

OpenStudy (experimentx):

potential ... of course!! ... the capacitance has changed due to charges.

OpenStudy (anonymous):

the potential

OpenStudy (experimentx):

and use ... energy stored = work done = E.d <-- integration

OpenStudy (anonymous):

yeah \[U=\frac 12 CV^2\] let's see if I can derive distance....

OpenStudy (anonymous):

\[U=\frac 12 C V^2\] \[d=\frac VE\]

OpenStudy (anonymous):

\[U=\frac 12 C (dE)^2\]

OpenStudy (anonymous):

1:9

OpenStudy (anonymous):

1:3

OpenStudy (anonymous):

\[U=\frac 12\frac {A\epsilon_0 V^2}{d}\]

OpenStudy (anonymous):

this seems ok.....should I think of this in terms of proportions?

OpenStudy (experimentx):

yep .. when you take ratio's they cancel out. |dw:1362580225186:dw|

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