Question

If y = 3^x(lnx^2) , find dy/dx.

Answer 1

Did you just need help calculating it?

Answer 2

yea

Answer 3

Is the equation? \[3^{x}*\ln(x^2)\]

Answer 4

yes

Answer 5

We would need to apply both the prodcut rule and chain rule

Answer 6

ok

Answer 7

We would need to start with the product rule so we take the derivative of the (first term times the second term without doing the derivative of it) plus (the first term times the derivative of the second term)

Answer 8

there is a quick little formula for finding the derivative of a constant to the x power

Answer 9

okay

Answer 10

If we have a to the x (where a is a constant)....if we want to find the derivative of it we would get (a^x)lna

Answer 11

ok

Answer 12

so go ahead and trying doing it

Answer 13

okay i'll try thanks

Answer 14

np

Answer 15

i got dy/dx = 2(3^x)/x - 3^x(ln3)(lnx^2)

Answer 16

let me quickly calculate it

Answer 17

ok

Answer 18

\[3^x*3\ln(x^2)+(2x/x^2)*3^x\]

Answer 19

Thats what I got and I'm pretty sure it is right

Answer 20

okay

Answer 21

Sorry I need to go but good luck