Question

I have the answer can someone check me.
In the 1940's the population of the tribbles on the island of Kent could be approximated according to the formula
P=573(1.021)^t
Where t is the number os years since 1940.
Find approximately how fast(in tribbles/yeat) the population was growing in 1942.

Answer 1

Take the derivative with respect to t. \[\frac{ d }{ dt } e^{at} = ae^{at}\]
What you can do is express
\[1.021 = e^{something}\]

Answer 2

so would the answer be 1.9326x10^20

Answer 3

No, you made two mistakes. One is that you used the wrong t; t is the years SINCE 1940.

Answer 4

so the the t=2

Answer 5

so then the answer would be 597.319

Answer 6

No, you haven't take the derivative properly.

Answer 7

I am confussed on what to do I guess

Answer 8

\[P = 573e^{at}\] You seem to have correctly found a to be ln(1.021). What is
\[\frac{ d }{ dt } 573e^{at}\] ?

Answer 9

397.173

Answer 10

What is it as a function of t?

Answer 11

I am confussed

Answer 12

o what about 4233.929

Answer 13

oh no I got it I think is the answer 838.929

Answer 14

Look at my first post, it gives the rule for finding the derivative.

Answer 15

ok I think I got it 2.062

Answer 16

is that answer correct

Answer 17

can you please tell me if my answer is right!!!!

Answer 18

It's not what I got. Try to find the expression for the rate of tribble growth\[\frac{ dP }{ dt }\]
Then see what the value of dP/dt is when t = 2.