Question

\[\frac{ 2 }{ 8x^2 }=\frac{ 1 }{ 8x }\]

Answer 1

Start by cross multiplying. What do you get?

Answer 2

I think it's x = 2

Answer 3

How did you get that answer?

Answer 4

umm.. one second..

Answer 5

I cross multiplied and got 8x^2 = 2 * 8x, which is, 8x^2 = 16x, then I divided it by 8 and got x=2

Answer 6

oops meant divided it by 8x

Answer 7

Good work! Your answer is correct.

Answer 8

yay! Can you help me with another one?

Answer 9

Go ahead with one more.

Answer 10

okay, that's the last one.

Answer 11

Using complete sentences, explain the steps to solve the equation using the LCD method.
\[\frac{ 3 }{ x+2 } + \frac{ 1 }{ 2x }=\frac{ 4 }{ x+2 }\]

Answer 12

I'm thinking it's like x = 1, but I don't think it's right...

Answer 13

The LCD of the denominators on the left hand side is 2x(x + 2)
Using this LCD the left hand side becomes
\[\frac{6x+x+2}{2x(x+2)}=\frac{7x+2}{2x(x+2)}\]
So the equation now becomes
\[\frac{7x+2}{2x(x+2)}=\frac{4}{x+2}\]
What do you get if you multiply both sides of the equation by (x + 2)?

Answer 14

Well the x+2 would cancel out. Right?

Answer 15

Good work! so we now get
\[\frac{7x+2}{2x}=\frac{4}{1}\]
Now cross multiply and what do you get?

Answer 16

umm 7x + 2 * 1 = 4 * 2x??

Answer 17

Correct
7x + 2 =8x
Now subtract 7x from both sides and you have it!

Answer 18

umm. x = 2?

Answer 19

Your answer is correct! Well done :)

Answer 20

YAY!!!!!!!!!!! THANK YOU SOOOOOOOO MUCH!!! YOU'RE LIKE MY HERO!! CUZ I'VE BEEN WORKING ON THIS TEST FOR LIKE ONE AND A HALF HOURS!!!! :DDDD

Answer 21

You're welcome :)