find the exact value : sin (-620 degrees)
are u sure that is -620 ?
yes
I already know it equals into 100 degrees, what I don't understand it actually finding the exact value for sin100 degrees.
yeah, 100 is not the special degrees.. need to long time to get its exact
I don't quite understand what your saying, I'm talking about Sum and Difference Identities.
i think u want simplify it by using Sum or Difference Identities, right ? sin(-620) = -sin(620) = -sin(2*360-100) = -sin(-100) = (-)(-)sin(100) = sin100 if u want simplify again, it can be sin100 = sin(90+10) = -cos10
It's +100, not -100
10 degree is not the special angle too, in trigono we can getting its exact value, but too longgggg :)
\(-620^\circ + 2\cdot 360^\circ = 100^\circ \)
i used identity sin(-x) = -sinx, first @wio
Sorry I think I wasn't clear about this question at the start. I have to use the formula: "sin(a +B) = sina cosB + cosa sinB " to find the exact value of 100 degrees
I can't use values such as 30, 45, or 60 degrees because they don't equal to 100 degrees
When you try to add 2 of them to eachother
yes, we cant use 30,45,60 deg! better searching google :)
I did! Which resulted hurting my hand from smacking it against my desk...
maybe, this file useful for u
and if ur question is -630 not -620, we can get it sin(-630) = -sin(630) = -sin(360+270) = -sin(270) = -(-1) = 1
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