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Write an equation in slope-intercept form for the line shown.
slope intercept form is of the form y=mx+b where b is the y intercept and m is the slope. in order ti find the equation given 2 points we have to find the slope of the line given by \[(y _{2}-y _{1})\div(x _{2}-x _{1})\] so m=(-1-4)/(2-0)=(-5/2)
A. y = 2/3 x + 2 B. y = 3/2 x - 4 C. y = 3x - 4 D. y = 2x - 1
then arranging the equation in the general equation of a line \[(y-y _{1})=m(x-x _{1})\] (y-(-4))=(3/2)(x-0)
sorry i got the slope wrong above it should be 3/2
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Its okay :)
then you solve for y y+4=(3/2)(x-0) y+4=(3/2)x y=(3/2)x-4
Thanks<3
do you understand what i did?
Yes:)
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