Question

Factor completely: 2x^3 + 4x^2 + 6x + 12
A.2[(x^2 + 3)(x + 2)]
B.(2x^2 + 6)(x + 2)
C.2[(x^2 + 2)(x + 3)]
D.Prime

Answer 1

Factor by grouping. Factor 2x^2 out of the first two terms.
Factor 6 out of the last two terms.
Then you will see that x+2 is a common factor. Factor.

Answer 2

Following @Mertsj instructions:

2x^3 + 4x^2 + 6x + 12 =

2x^2( x + 2) + 6(x + 2)

Note that (x+2) is a common factor.

Answer 3

So, 2x^2( x + 2) + 6(x + 2) = ( x + 2)* ( ? + ? ) @isabellaxo