can anyone help me on linear independent
We can. Just post the question!
lol
can we use column space approach to check wether matrix is linaer independent?
can't you put the matrix into upper row echelon form, then make the free variables go to the opposite side, and solve for the pivots through substitution
are you finding the basis
not..it just to check whether {(2,0,1),(2,0,-1),(0,0,1)} is linear independent
what should i do..it is same if i use row space?
those can be a matrix. but ok
not familiar with rs, gonna look
The easiest way is to get it into row reduced form. If it is linearly independent, it will have no free variables.
iit's possible for me to get same answer if i use row space and column space?
I know for sure it would work if you let each vector be a row of the matrix.
next..can you use column space approach to find a,b that satisfy (0,0,1)=a(2,0,1)=b(2,0,-1)?
Linearly independent means that the vectors are all separate of each other and can't be used to make the others. For example, a vector in the x-direction and a vector in the y-direction are linearly independent because no amount of x-vectors can make a y-vector.
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