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Linear Algebra 19 Online
OpenStudy (anonymous):

can anyone help me on linear independent

geerky42 (geerky42):

We can. Just post the question!

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

can we use column space approach to check wether matrix is linaer independent?

OpenStudy (anonymous):

can't you put the matrix into upper row echelon form, then make the free variables go to the opposite side, and solve for the pivots through substitution

OpenStudy (anonymous):

are you finding the basis

OpenStudy (anonymous):

not..it just to check whether {(2,0,1),(2,0,-1),(0,0,1)} is linear independent

OpenStudy (anonymous):

what should i do..it is same if i use row space?

OpenStudy (anonymous):

those can be a matrix. but ok

OpenStudy (anonymous):

not familiar with rs, gonna look

OpenStudy (anonymous):

The easiest way is to get it into row reduced form. If it is linearly independent, it will have no free variables.

OpenStudy (anonymous):

iit's possible for me to get same answer if i use row space and column space?

OpenStudy (anonymous):

I know for sure it would work if you let each vector be a row of the matrix.

OpenStudy (anonymous):

next..can you use column space approach to find a,b that satisfy (0,0,1)=a(2,0,1)=b(2,0,-1)?

OpenStudy (kainui):

Linearly independent means that the vectors are all separate of each other and can't be used to make the others. For example, a vector in the x-direction and a vector in the y-direction are linearly independent because no amount of x-vectors can make a y-vector.

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