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One mole of an ideal gas is held at standard conditions. At what Kelvin temperature would the pressure be doubled?
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keeping the volume constant right
PV=nRT P/T = constant P1/T2 =P2/T1 T2=P1 T1 /P2 but P2 is equal to 2P1 in this case T2=P1T1/2P1=1/2 T1 therefore temperature should be half of the initial temperature
ok got it Thank you
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