Question

when do we find integrating factor and how do we find it?

Answer 1

You normally integrate when adding dimension. i.e. area to volume

How subtract 1 from the exponent and divide the quantity by the new exponent.

Answer 2

will you pls give one example?

Answer 3

a square for example. area is length squared we'll say length is x & x = 4
So
A(x)= [4^{2}]=16 or x^2
Now to find the the volume of a cube we could make it x^3 or we could account for the new dimension by integration:
\[\int\limits_{0}^{4}(x ^{2})dx=((x^3)\div3) [0,4]\]

After that it's just a matter of resolving the integrand by substituting 4 and 0 in for x and resolving the difference.

Answer 4

what does single integral tells us and how is it different from double integral?