$$cos^{-1}\left[cos\left(-\frac \pi 3\right)\right]$$

Question

anonymous · Answer

$$cos\alpha=\frac 12$$
$$\alpha =\frac \pi 3$$

zepdrix · Answer

I'm a little confused by the way you wrote that. Perhaps you're taking a different approach than I would :) But it seems to have worked out.

anonymous · Answer

my ultimate goal is to find alpha correct?

anonymous · Answer

LOL....I'm sorry

zepdrix · Answer

$$\large \cos^{-1}\left[\cos\left(-\frac \pi 3\right)\right]=\alpha$$

Since our outer function is an inverse trig, we're ultimately looking for an angle. Yes I suppose that's true! :)

I guess I understand what you did, you just showed the last 2 little steps I guess.

anonymous · Answer

yep I only showed the last two steps....let's do some sum and difference angle problems :)

experimentx · Answer

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