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Mathematics 18 Online
OpenStudy (anonymous):

A snow cone is a tasty treat with flavored ice and a spherical bubble gum ball at the bottom. The radius of the cone is 1.25 inches, and its height is 2.75 inches. If the diameter of the bubble gum ball is 0.5 inches, what is the closest approximation of the volume of the cone that can be filled with flavored ice? 4.43 in^3 0.07 in^3 13.50 in^3 4.50 in^3

OpenStudy (anonymous):

OpenStudy (anonymous):

@Mertsj please help?

OpenStudy (anonymous):

@satellite73 ?

OpenStudy (mertsj):

Volume of the cone -volume of the bubble gum \[\frac{1}{3}\pi r^2h-\frac{4}{3}\pi r^3\]

OpenStudy (mertsj):

\[\frac{1}{3}(\pi)(1.25)^2(2.75)-\frac{4}{3}\pi (.25)^3\]

OpenStudy (mertsj):

I'll leave the arithmetic to you

OpenStudy (anonymous):

I have no idea how to solve that...

OpenStudy (mertsj):

So you don't know how to square a number or you don't know how to multiply or what?

OpenStudy (anonymous):

I just don't know how to put that in a calculator and solve it.

OpenStudy (mertsj):

type 1 divided by 3 times3.14159 times1.25 times 1.25 times2.75 equals

OpenStudy (mertsj):

Write that number down on a piece of paper.

OpenStudy (mertsj):

Type 4 divided by 3 times3.14159 times .25 times .25 times .25 equals

OpenStudy (mertsj):

Write that number down on a piece of paper.

OpenStudy (mertsj):

Type the first number you wrote down minus the second number you wrote down equals. That is your answer

OpenStudy (anonymous):

Ohhhhhh. okay. Thank you :)

OpenStudy (mertsj):

yw

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