Question

]Which of the following represents the quantity of x to the second minus nine, all over the quantity of x to the second minus three x in simplified form?

Answer 1

(x^2 - 9) / (x^2 - 3x)
isn`t this a better way to ask a question??

this can be written as (x-3)(x+3)/ x(x-3) clear??
now can you get to the final answer?

Answer 2

$$\frac{(x^2 - 9)}{(x^2 - 3x)}= \frac{(x-3)(x+3)}{x(x-3)} $$

Answer 3

Harsimram beat me to it. :-)

And just for the record, something-or-other "to the second" is stated as something-or-other "squared".

Likewise, anything to the 3rd power is "cubed".

To the best of my knowledge, squares and cubes are the only roots/powers which enjoy their own special identity, so all other exponents are simply stated "to the power".

Answer 4

here are the choices, im still confused about this.. 1 minus 3 over x

1 plus 3 over x

x minus 3, all over x

x plus 3, all over x

Answer 5

cancel the common x-3 factor and you get (x+3)/x = 1 + 3/x
clear??

Answer 6

Look at Skullpatrol's expression.

Answer 7

is it the 3rd answer?

Answer 8

1 and 3 both are correct