Please help...
Determine the measure of side c, given:
a=3m
b=4m
B=41deg
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OpenStudy (aravindg):
tried cosine rule ?
OpenStudy (anonymous):
im not sure how to do this at all....
OpenStudy (aravindg):
do u knw cosine rule ?
OpenStudy (anonymous):
i have just started learning about it
OpenStudy (aravindg):
ok
\[\cos B=\dfrac{a^2+c^2-b^2}{2ac} \]
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OpenStudy (aravindg):
now solve for b
OpenStudy (anonymous):
yea good cosine rule,,my answer is b=2.44 (approx.)
OpenStudy (dan815):
u could use sin law too i think
OpenStudy (anonymous):
sorry 1.22
OpenStudy (aravindg):
@dan815 sin law wont work cause we need two angles :/
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OpenStudy (dan815):
sin <b/b=sin<a=a sin<(180-(a+b))/c and solve for C
OpenStudy (dan815):
use my equation < means angle
OpenStudy (anonymous):
actually my options are:
1.6m
4.5m
0.1m
5.7m
I thought it was 1.6m?
OpenStudy (anonymous):
am I wrong?
OpenStudy (anonymous):
actually it was 5.7 after I figured it out.. Thanks though
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OpenStudy (dan815):
did u use my formula!
OpenStudy (anonymous):
yea approx.
OpenStudy (anonymous):
yes thank you
OpenStudy (dan815):
np :)
OpenStudy (dan815):
if u remember that you need atleast 3 pieces of information to solve a triangle
and that if the angle given is the angle of the opposite side then you can always use sin law
if they give u like side a and b but give you angle C then you have to use cos law if its not a right angle triangle