Please help... Determine the measure of side c, given: a=3m b=4m B=41deg
tried cosine rule ?
im not sure how to do this at all....
do u knw cosine rule ?
i have just started learning about it
ok \[\cos B=\dfrac{a^2+c^2-b^2}{2ac} \]
now solve for b
yea good cosine rule,,my answer is b=2.44 (approx.)
u could use sin law too i think
sorry 1.22
@dan815 sin law wont work cause we need two angles :/
sin <b/b=sin<a=a sin<(180-(a+b))/c and solve for C
use my equation < means angle
actually my options are: 1.6m 4.5m 0.1m 5.7m I thought it was 1.6m?
am I wrong?
actually it was 5.7 after I figured it out.. Thanks though
did u use my formula!
yea approx.
yes thank you
np :)
if u remember that you need atleast 3 pieces of information to solve a triangle and that if the angle given is the angle of the opposite side then you can always use sin law if they give u like side a and b but give you angle C then you have to use cos law if its not a right angle triangle
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