Question

If V=10V.
I= 0.

There is no demand for current in the circuit.
Lets say it was "off".
And A magnet passes through the circuit, can a magnet field be generated?

Is a magnetic field created due to flow of current I, or the presence of V alone can do that?

Answer 1

@TuringTest @Jemurray3 @experimentX

Answer 2

If there is no current, that means charges are not in motion,
It won't have a magnetic field associated with it.
When there is just a potential, there is only static electric field. Charges are static. So no magnetic field

Answer 3

You might think so...

...until you drop a magnet down a copper tube. :-)

https://www.youtube.com/watch?v=_GpuySSf2so

Answer 4

Or an aluminum tube, for that matter. :-)

Answer 5

@qweqwe123123123123111

Yea good point. I thought so as well... But still, if U had 0 voltage no movement of charges...
Maybe there is a static field that a magnet is passing through?
as @fringe said...

Answer 6

@Jemurray3
Whats your take here?

Answer 7

@Shane_B

Answer 8

current is generated due to changing magnetic flux, that is certainly change in magnetic field , and changing current also produces magnetic field , so a magnet passing through the wire has nothing to do with circuit, yea for a moment it will generate an instantaneous current but wont be considerable , depends on the strength of magnetic field.

Answer 9

@ghazi

So... When the current is zero in a circuit does that mean there is no change in B = No B at all?
Lets say a magnet is passing through that circuit, and voltage is still 0.
Will a B field other than the magnet exist?

Answer 10

The point is having \[I \neq 0 \]
That would generated a \[B field\]
Copper pie has current passing though it I guess...?!
I don't know this makes no sense...