Question

.-.

Answer 1

yeah i believe it's sometimes:)

Answer 2

you can always factor, just not always using integers

Answer 3

if the roots are \(1\) and \(3\) then you can factor as \((x-1)(x-3)\) but if the solutions are \(2+\sqrt5\) and \(2-\sqrt5\) then you can factor as
\[(x-(2+\sqrt5))(x-(2-\sqrt5))\]

Answer 4

This is slightly goofy, but if we assume "nice factors", then sometimes is the answer

Answer 5

YAAY~! ^_^
Ari! First question I ever saw you post! ^_^

Answer 6

@phi i agree with him

Answer 7

on the other hand if some one says "pick a number" you are not likely to say \(2+\sqrt5\) so it is unlikely you can actually "solve' the equation by factoring

Answer 8

YAY!
YOUR NOT A SUPERHERO!!
YOU HAVE MATH
TOO! ^_^

Answer 9

Yes, when you can't factor it, use the quadratic formula, and then finally, you will be able to factor it.