A student purchases bottled drinks and canned drinks for a party. She purchases a total of 49 drinks for the party at a total cost of $47.55. If bottled drinks each cost $1.15 and canned drinks each cost $.75, How many of each type of drink did she purchase?

Question

anonymous · Answer

49 drinks = 47.55

Let number of Canned = C, and  number of Bottled = B

if you wanted to know the cost of a certain amount of bottles and cans you'd use expression such as

$$1.15*B = Cost -of- B$$
$$.75*C=Cost-of-C$$ if we know that the cost of both must equal 47.55,

$$1.15B+.75C=47.55$$
this is one equation. We also know that the number of bottles and number of cans must equal 49 all together

$$B+C=49$$

anonymous · Answer

use the second to solve the first

$$B=49-C$$

put this into the first equation and solve for C
$$1.15(49-C)+.75C=47.55$$

anonymous · Answer

i'm going to leave this at this

anonymous · Answer

if you need more help let me know

anonymous · Answer

Thank you s much! That helped me a lot