Question

Momentum of a body is doubled.
%Change in KE=?

Answer 1

attempt ?

Answer 2

no :P

Answer 3

change in p = (p2-p1)/p1 = 2

Answer 4

or
(v2 - v1)/v1 =2

Answer 5

you have to calculate

( v2 ^2 - v1 ^2 )/v1 ^2

Answer 6

4

Answer 7

I am too lazy to calculate, sorry :|

Answer 8

:/

Answer 9

Momentum!

Answer 10

i get ( v2 ^2 - v1 ^2 )/v1 ^2 =8

Answer 11

(v2 - v1)/v1 =2 -----> v2 = 3v1

Answer 12

how?

Answer 13

@shubhamsrg got it 1/2

Answer 14

v2 = 3v1
( v2 ^2 - v1 ^2 )/v1 ^2
= ( 9v1 ^2 - v1 ^2 )/v1 ^2
=8

Answer 15

Thanks :O

Answer 16

welcome ^_^

Answer 17

800%?right ;O

Answer 18

correct.

Answer 19

\[\rm Kinetic ~energy = \dfrac{1}{2}mv^2\]\[\rm momentum = mv\]^_^