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Need help: a2 + 12ab + 27b2 Factoring!
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\[a ^{2} + 12ab + 27b ^{2}\]
can you find 2 numbers with product = 27 and sum =12 ?
No?
Sorry, I asked the wrong question. I'll post the correct one.
*facepalm* yes 3 & 9
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good.
so, split 12ab = 3ab and 9ab
\(a^2+3ab+9ab+27b^2 \) factor out a from 1st 2 terms and 9b from last two, what u get ?
This is what I have so far . . . a2 + 12ab + 27b^2 3*9 = 27 3 + 9 = 12 (ab + 3) (ab + 9)??
\(a^2+3ab+9ab+27b^2 = a(a+3b)+9b(a+3b)\\= (a+3b)(a+9b)\) got this ?
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ahhh ok
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