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A 6-sided die is rolled three times. What is the probability that all three rolls resulted in different numbers? 0.500 0.556 0.578 0.596 0.606
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@jim_thompson5910
The first time it may be any number. The second time, one of the numbers shouldn't come up. Probability 5/6. Third time: only 4 possibilities left, so 4/6. Total probability: \(1 \cdot \frac{5}{6}\cdot \frac{4}{6}=...\)
5/9?
b
First multiply, then simplify: 20/36=10/18=5/9
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So, yes it's b.
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