Question

I'm supposed to be able to solve ln1 without using a calculator. ...how?

Answer 1

if \(\ln a = b, then \: a=e^b \)
let ln 1 =x
then e^x = 1
which value of 'x' you think, satisfies this ?

Answer 2

... 0 :)

Answer 3

thas correct, infact in any base of log, the answer will be 0
ln 1=0 , log1=0 , log_n 1=0
because anything^x = 1 gives you x=0