Please somebody- It's just a simple check to see if I have the right answer (pretty easy) :) Just want to check if this is correct in interval notation. Solve the inequality, write in interval or union of interval notation: x^3+x^2<=9x+9 Answer: (x <= -3] and [-1<=x<=3] Interval notation: (-infinity, -3] U [-1,3]
correct
Really?
Are you sure it's a union @mathgeek!
@amistre64 Can you double check this for me please?
ya one sec
1st equation: x^3+x^2-9x-9 Break it up in two parts x^3+x^2 and -9x-9 Pull out common factors x^2(x+1) and -9(x+1) Since (x+1) match on both sides just use it once, then put the outside terms in another group (x+1)(x^2-9) Then see if the terms cant be reduced further (x+1)(x+3)(x-3) 2nd equation Basically there isn't an easy way to do this. Just try to remember what cubic factoring looks like. It is all similar to this. (y+1)(y^2-y+1)
thats what i got
essential i get a boundary line: x^3+x^2 = 9x+9 x^3+x^2 - 9x- 9 = 0 which breaks into 3 parts: (x+3)(x+1)(x-3); zeros are x=3,-1,-3 mark these as 0s on a number line <----------0--------0--------0-----------> -3 -1 3 now we can determine the sign value for the 4 segments that are NOT 0, simply pick a value and test it out -5 -2 0 5 <----------0--------0--------0-----------> -3 -1 3 -64 5 -9 96 so we have a map that is: -, + -, + and we want all the segments that are 0 or positive x = [-3,-1] OR [3,inf)
pffft, that was spose to be a <= 0
x = (-inf,-3] OR [-1,3]
i was right though
Lol-You lost me on the boundary line amistre. So I can put either (-inf, -3] as the correct answer OR [-1,-3]?
if its asking for ALL values that make it a solution; you have to use the OR and include both ranges
exactly
mathgeek! was correct ;) the boundary line was a thought i had if we were going to graph this on paper .... it was a spurious thought
hahah u can call me emilee my username is pretty stupid
gotcha- it doesn't ask for the range it just asks me to solve the inequality in interval or union of interval notation. When I got the second [-1,3] i threw me off...
thank you emilee :)
|dw:1363030020144:dw|
Join our real-time social learning platform and learn together with your friends!