Question

algebra II, 7 questions, please help? I've tried everything and I still don't know these

Answer 1

I will fan and give medal

Answer 2

i will try if i can help

Answer 3

give me one or some of them

Answer 4

question 2: rationalize the denomenator

Answer 5

4.66001381463

Answer 6

thats not one of my choices

Answer 7

show me your choices

Answer 8

16.8209311619

Answer 9

is that one of your choices?

Answer 10

or 9.7

Answer 11

im pretty sure its 9.7

Answer 12

MY CHOICES ARE:

Answer 13

Rationalize the denominator by multiplying by its conjugate:\[\frac3{6-\sqrt5}\times\frac{6+\sqrt5}{6+\sqrt5}=\frac{18+3\sqrt5}{31}\]

Answer 14

There is seven questions, the first one im trying to do is

Answer 15

Distribute:\[\sqrt5(10-4\sqrt2)=10\sqrt5-4\sqrt10\]

Answer 16

multiply by
6+sqrt(x)

Answer 17

identify the conjugate of

Answer 18

4-sqrt(7) i think

Answer 19

The conjugate of an expression with a square root like \(a+b\sqrt{c}\) is always given by \(a-b\sqrt{c}\). The point of this whole concept is that it aids in simplifying expressions, since multiplying the expression by its conjugate yields a difference of squares free of radicals: \((a+b\sqrt{c})(a-b\sqrt{c})=a^2-ab\sqrt{c}+ab\sqrt{c}-b^2\sqrt{c}^2=a^2-b^2c\)!

Answer 20

distribute

Answer 21

would the answer be this?

Answer 22

Distribute: \[\begin{align*}(4-\sqrt3)(12+5\sqrt3)&=4(12+5\sqrt3)-\sqrt3(12+5\sqrt3)\\&=48+20\sqrt3-12\sqrt3-5\sqrt3^2\\&=48+8\sqrt3-15\\&=33+8\sqrt3\end{align*}\]

Answer 23

rationalize the denominator

Answer 24

Multiply both the numerator and denominator by \(\sqrt2\) to get rid of your radical.\[\frac3{\sqrt2}\times\frac{\sqrt2}{\sqrt2}=\frac{3\sqrt2}{\sqrt2^2}=\frac{3\sqrt2}2\]

Answer 25

you should know better than to post a whole assignment here without even trying it first !!

Answer 26

\[\sqrt{10}x \sqrt{8}\]

Answer 27

the x is multiply