I got a “No Solution” for the answer. Can someone double check for me to make sure I’m doing the steps correctly? Please Solve for x ln(x)=ln(x-4)+ln(6) Simplifying ln(x) = ln(x + -4) + ln(6) Multiply ln * x lnx = ln(x + -4) + ln(6) Reorder the terms for easier multiplication: lnx = -4ln + lnx + 6ln Reorder the terms: lnx = -4ln + 6ln + lnx Combine like terms: -4ln + 6ln = 2ln lnx = 2ln + lnx Add '-1lnx' to each side of the equation. lnx + -1lnx = 2ln + lnx + -1lnx Combine like terms:2ln + -2ln = 0 -2ln = 0 Divide each side by '-2'.ln = 0 Answer: ln=0
im back
u need help
Just a quick check please. The equation is ln(x)=ln(x-4)+ln6 and I have to solve for x. I came up with a no solution for x.
ur answer is correct
You rock!! Thank you
np!
\[\ln x = \ln(x-4)+\ln6\] \[\ln x - \ln(x-4)-\ln6\ = 0\] \[\ln \frac{ x }{ 6(x-4) } = 0\] \[e^{\ln \frac{ x }{ 6(x-4) }} = e^{0}\] \[\frac{ x }{ 6(x-4) } = 1\] \[x = \frac{ 24 }{ 5 }\]
@mathgeek! I already put the answer down as "no solution" is he correct?
correct! wait let me make sure
yeah its right!
He's right or your right O_o
we both are
hahaha- so it just depends on how you work the problem right?
I'm not sure how there can be no solution and x=24/5... eeek
\[\ln (x)?\] Is that in the equation?
exactly take it step by step
ok. I ran it through 2 calculators as a double chekc and 2 said no solution, and 2 came up with 25/5.
yeah i think your right
correction 24/5. Guess it just depends on how you work it out... You can either get no solution or 24/5 as an answer- VERY Confusing.
if its the mathematical ln function then its 24/5 is the right answer!
very confusing!lol
Aggghhhhh- this is why I do not do math on purpose.
use the property of log, we have to simplify in right side, first ln(x)=ln(x-4)+ln(6) ln(x)=ln{(x-4)6} now, cancel out the ln for both sides we get x = (x-4)6 x = 6x-24 24 = 6x-x 24 = 5x x=24/5
S@#T guess it's wrong then...
It is 24/5!!
yeah good job!
yup, in maths dont do more guess! :P
i just did the problem on paper nd the answer is 24/5
Emmille- You said that the "no solution" was correct... I'm telling Stanford! lol
Thanks RadEn
you're welcome :)
ugh Stanford is gonna be pissed
Yes, yes they are!
:(
maybe you'll get the next one- don't fret :)
lmao
need anymore help before i log off
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