Question

3. A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation
y = –0.04x2 + 8.3x + 4.3 , where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land? Round your answer to the nearest hundredth meter. (1 point)
A) 208.02 m
B) 416.03 m
C) 0.52 m
D) 208.19 m

Answer 1

When it hit the ground=>y = 0
=>By y = –0.04x^2 + 8.3x + 4.3
=>0.04x^2 - 8.3x - 4.3 = 0
=>x = [-(-8.3) +/- √{(-8.3)^2 - 4 x 0.04 x (-4.3)}]/[2 x 0.04]
=>x = [8.3 +/- 8.34]/[0.08]
=>x = 208.02 m
Answer: A.)

Answer 2

thanks

Answer 3

np:)