Ask
your own question, for FREE!

Trigonometry
54 Online

OpenStudy (andu1854):

(cos^3x - sin^3x)/(cosx - sinx) = 1 + sinx cosx; Verify the Identity. I am not sure how to get to the answer. Any help getting me started would be greatly appreciated.

Still Need Help?

Join the QuestionCove community and study together with friends!

OpenStudy (tkhunny):

You should recognize the form of the numerator. A difference of cubes. This can be factored.

OpenStudy (andu1854):

Can you factor out a sincos to then create sincos(sin^2 +cos^2

OpenStudy (anonymous):

\(a^3-b^3=(a-b)(a^2+ab+b^2)\)

OpenStudy (anonymous):

As tkhunny mentioned, you have something that looks like \[\frac{a^3-b^3}{a-b}\] Using the difference of cubes pattern, you can factor to get \[\frac{(a-b)(a^2+ab+b^2)}{(a-b)}\]

OpenStudy (andu1854):

Thank you very much... let me see what I do next, but that was very cool...

Still Need Help?

Join the QuestionCove community and study together with friends!

OpenStudy (andu1854):

Thank you for the help on this one... I got it...

Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!

Join our real-time social learning platform and learn together with your friends!

Latest Questions

Ray11:
Why do teachers not teach us taxes, but think finding x is going to help in life?

3 hours ago
8 Replies
0 Medals

whyjustwhy:
i counted my sneezes today. currently at 47 rn. how do I stop it and why is this happening.

4 hours ago
3 Replies
1 Medal