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Differential Equations
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OpenStudy (anonymous):

diffrentation cos3x

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OpenStudy (anonymous):

the derivative of cosine is minus sine

OpenStudy (anonymous):

so the derivative of \[\cos(3x)\] is \[-3\sin(3x)\] by the chain rule

OpenStudy (anonymous):

got it or u need explanation

OpenStudy (anonymous):

how about sin^3x

OpenStudy (anonymous):

derivative of sin is cos

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OpenStudy (anonymous):

\[\huge \sin^3 x=(\sin x)^3\] Use the chain rule. \[\huge (\sin x)^3=3(\cos x)(\sin x)^{3-1}\] \[\huge =3(\cos x)(\sin x)^{2}\]

OpenStudy (anonymous):

never mind he got it

OpenStudy (anonymous):

\[\sin^3(x)=(\sin(x))^3\] so by the chain rule you would get \[3(\sin(x))^2\cos(x)\]

OpenStudy (anonymous):

thank U @satellite73 @Azteck

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