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Differential Equations
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diffrentation cos3x
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the derivative of cosine is minus sine
so the derivative of \[\cos(3x)\] is \[-3\sin(3x)\] by the chain rule
got it or u need explanation
how about sin^3x
derivative of sin is cos
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\[\huge \sin^3 x=(\sin x)^3\] Use the chain rule. \[\huge (\sin x)^3=3(\cos x)(\sin x)^{3-1}\] \[\huge =3(\cos x)(\sin x)^{2}\]
never mind he got it
\[\sin^3(x)=(\sin(x))^3\] so by the chain rule you would get \[3(\sin(x))^2\cos(x)\]
thank U @satellite73 @Azteck
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