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Chemistry 14 Online
OpenStudy (anonymous):

How many moles of ethane (C2H6) would be needed to react with 62.3 grams of oxygen gas? Unbalanced equation: C2H6 + O2 â ' CO2 + H2O Show, or explain, all of your work along with the final answer.

OpenStudy (chmvijay):

can u balance and write the reaction

OpenStudy (anonymous):

2C2H6 + 7O2 --> 4CO2 + 6H2O right?

OpenStudy (chmvijay):

right

OpenStudy (chmvijay):

what is moleuclar weight of O2

OpenStudy (anonymous):

32.00

OpenStudy (chmvijay):

1mole of O2= 32g 7*32=224 g 224 g of Oxygen reacts with 2 moles of ethane 62.3 g of oxygen =2*62.3/224=0.5 moles of ethane u got it

OpenStudy (anonymous):

That's the answer right? because if it is, you explain this sooo much easier than my chemistry teacher aha.

OpenStudy (chmvijay):

in what way she explained you can i know

OpenStudy (anonymous):

he goes through it with us, but he does not explain how to get the moles or any of it. He makes us pretty much explain it to ourselves.

OpenStudy (chmvijay):

humnnn any way i am sure its correct!!!

OpenStudy (anonymous):

Thank you VERY much. :)

OpenStudy (chmvijay):

ur welcome

OpenStudy (anonymous):

So that would mean that How many grams of sodium sulfide can be produced when 45.3 g Na react with 105 g S? Unbalanced equation: Na + S â ' Na2S Show, or explain, all of your work along with the final answer. 2Na + S --> Na2S 32.07 grams of sulfur react with 2 moles of sodium..l Now I'm stuck.

OpenStudy (chmvijay):

molecular weight of Na2S can u tell

OpenStudy (anonymous):

78.05 right?

OpenStudy (chmvijay):

wait for a while

OpenStudy (chmvijay):

here you have to find the first limiting reagent and then have to solve the reaction

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