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it is given that 2 is one of the roots of the quadratic equation x^2-5x+k=0. find the value of k.
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(x - 2)(x + ?) = x^2 - 5x + k
-2*? = k
\[x^2-5x+k=0\]now since 2 is one of the root so if we substitute x=2 in the equation the equation should be equal to 0 because 2 is a factor of it \[(2)^2-5*2+k=0\]\[4-10+k=0\]\[k=6\]
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