Ask your own question, for FREE!
Mathematics 64 Online
OpenStudy (anonymous):

Graph the circle Given x^2+ y^2- 4x + 8y + 16 = 0 When solving for a circle I did the following steps: Place in standard notation. x^2- 4x + y^2+ 8y = -16 Complete the square. x^2- 4x + 4 + y^2+ 8y + 16 = -16 + 4 +16 (x - 2) ^2 + (y + 4) ^2= 4 = 2^2 The equation is now written in standard form. The center is (2 ,-4) and the radius is 2.

OpenStudy (anonymous):

So my circle would have points that look like this: Center= 2,-4 2,-2 0,-4 4,-4 2,-6

OpenStudy (anonymous):

|dw:1363115105166:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!