Question

. If l is the side of a square and dl/dt =0.2 m/s ,then what is the rate of increase in area when l=5m ? i)2m²/s ii) 1m²/s iii)4m²/s iv)3m²/s

Answer 1

Area of square A = l^2
Rate of Increase in Area = dA/dt = (dA/dl)* (dl/dt) = ....?

Answer 2

Yes!!! i GOT AN answer.
we need to find ; dA/dt=?
Now,
dA/dt=d(l^2)/dt
=2l*dl/dt
= 2*5*0.2
= 2
hence, answer is 1

Answer 3

thats correct! good work :)