Anyone Really good at Solving Radical Equations?
I guess i can give it a shot . Let's go !
alright then
I'm looking for "x" right ?
yeah and identify any extraneous solutions, it would also help if you showed your work.
the first 1 is √8 +1 not 11
Well , for the first one the answer is x=3 8*3+1 = 25 And the square root of 25 is 5
\[\sqrt{x-7}+5=11\] subtract 5\[\sqrt{x-7}=6\] square both sides \[x-7=36\] add 7\[x=43\]
\[-4\sqrt{x+9}=20\] has no solution because the left hand side is negative and the right hand side is positive
\[\sqrt{6x+5}=\sqrt{53}\] square both sides and solve \[6x+5=53\]
Wow dude, you just blew me away.
For the last one , x=3 2+4=6 3+6 = 9 The square root of 9 is 3
i actually understand this now, thanks so much you guys.
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