Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

See attachment

OpenStudy (anonymous):

OpenStudy (anonymous):

@Mertsj

OpenStudy (mertsj):

how many cards in all?

OpenStudy (anonymous):

10

OpenStudy (mertsj):

How many red?

OpenStudy (anonymous):

4

OpenStudy (mertsj):

What's the probability you will draw a red card?

OpenStudy (anonymous):

4/10?

OpenStudy (mertsj):

Reduce it.

OpenStudy (anonymous):

ok 2/5

OpenStudy (mertsj):

So you draw the red card, replace it and draw another card. What is the probability the next card you draw will be red?

OpenStudy (anonymous):

well, if you draw a red card thats 4/10, then if u replace it (put it back) the chances of getting a red card don't change

OpenStudy (mertsj):

So why don't you just say 2/5?

OpenStudy (anonymous):

so the answer would be D?

OpenStudy (mertsj):

Multiply those two probabilities.

OpenStudy (anonymous):

2 /5 x 2/5 = 4/25

OpenStudy (mertsj):

yep

OpenStudy (anonymous):

tnx, i get it now.

OpenStudy (mertsj):

yw

OpenStudy (anonymous):

:)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!