Question

Ok, polar coords double integral help please!

Answer 1

So, I think that this should be done in polar coords, so the integral should look like this right?

\[\int\limits_{0}^{\pi} \int\limits_{3}^{6} (x^{2}-2y^{2})r dr d(\theta)\]

Answer 2

But now I need to convert the function inside to polar right?
using the identities: \[x = rcos(\theta)\] and \[y=rsin(\theta)\] right?